PTS Reinaldi Akmal (30) XI IPS 2
![Gambar](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi7lJom9BfId92WRLa_MsRXiL9FtPTG8PadNr7RVlLY4vakvewfUhsXyAoRHHyh6VUQg-d20lJMCDobv9_Bg8IbUERH5XXl9qg2nRRU8lB5x8cs3xihfF9xxxWrQIBbWO3fvojvUKlafVU/w640-h406/WhatsApp+Image+2021-02-16+at+08.08.29.jpeg)
Nama : Reinaldi Akmal (30) Kelas : XI IPS 2 Jawaban PTS Genap SOAL JAWABAN 1. 2. 3. 4. 5. a) 0 m/s b) v(t) = 5t - 1/2 t^2 a(t) = 5 - t a(3) = 5 - 3 a(3) = 2 percepatan pada saat t mendekati 3 detik 2 m/s^2 SOAL JAWABAN 1. f(x)=(2x+3)³ =(2x+3)(2x+3)(2x+3) =(4x²+12x+9)(2x+3) =(8x³+36x²+54x+27) f'(x) =24x²+72x+54 2. 3. turunan pertama dari f(x)=(2-6x)³ adalah f(x) = (2 - 6x)^3 f'(x) = 3 . (2 - 6x)^2 . (-6) f'(x) = -18 . (2 - 6x)^2 4. 5. 6. 7. 8. 9. 10. SOAL JAWABAN 1. Lim = 2x + 3 x² X →2 = 2(2) + 3(2)² = 4 + 3(4) = 4 + 12 = 16 2. Lim = (x²-5)³ X →-3 = ((-3)²- 5)² = (9-5)³ = 4³ = 64 3. 4. 5. 6. 7. 8. 9. nilai lim x mendekati a (f(x)+ 1 )² - 3f(x) adalah langsung ganti f(x) jadi p maka (p + 1)² - 3p = p² + 2p + 1 - 3p = p² - p + 1 10. Lim 2x² - x - 3 per 3x² + 8x + 5 x->1 lim x->1 (x+1) (2x-3) / (x+1) (3x+5) = lim x->1 (2x-3) / (3x+5) = -1/8 SOAL JAWABAN 1. 2. L persegi = s² f(x) = ax n